WHAT IS SERIES RC CIRCUITS?
Consider RC series circuit is shown in the figure (i), a pure resistance R and a purecapacitance C are connected in series.
r. m. s value of applied voltage = V
Current through R and L = I (Same current )
Reference phasor = I (Same current )
Voltage drop across the resistance = VR = I R (in − phase with current )
Voltage drop across the capacitor = VC = I XC (I leads the V by 90°
)
Voltage V = Vector sum of VR and VC
Phase angle difference between V & I = θ
From phasor diagram, V 2 = VR 2 + VC2
V = √VR 2 + VC 2 = √(IR) 2 + (IXC)2
= I√R2 + XC 2
V
--- = √R2 + XC2
I
Z = √R2 + XC 2
XC
tan θ = ---------
R
XC
θ = tan−1 (---------)
R
XC
tan θ =-----
R
Average Power:
Instantaneous current (v) = Vm sin ωt
Instantaneous voltage (i) = Im sin(ωt + θ)
Phase angle between v & i = θ
XC
Power factor (cos θ) = cos [tan−1 (-------) ]
R
Relationship between v & i = Current leads the voltage by θ
Instantaneous power : p = v x i
Instantaneous power : p = Vm sin ωt x Im sin(ωt + θ)
p = Vm Im [sin ωt x sin(ωt + θ)]
cos(−θ) + cos(2ωt + θ)
p = Vm Im [ ---------------------------------------]
2
Vm Im Vm Im
p = ----------- cos θ − ------------- cos(2ωt + θ)
2 2
The average power over one
complet cycle = Pav
1 2π
Average power : Pav =---------∫ p dθ
2π 0
1 2π Vm Im Vm Im
Pav =--------∫ ----------- cos θ − -----------cos(2ωt + θ)dθ
2π 0 2 2
2π
1 Vm Im
Pav =-------- ----------- ∫ cos θ − cos(2ωt + θ) dθ
2π . 2
0
Vm Im
Pav =------------- cos θ
2
Vm Im
Pav =------ ------- cos θ
√2 √2
Pav = V I cos θ
Where, V and I are rms values

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